BOJ 6721 - Backward numbers [C++]

문제

링크

풀이

#include <iostream>
using namespace std;
 
int reverse(int x) {
  int ret = 0;
  while (x) {
    ret = ret * 10 + x % 10;
    x /= 10;
  }
  return ret;
}
 
void solve(void) {
  int a, b; cin >> a >> b;
 
  cout << reverse(reverse(a) + reverse(b)) << "\n";
}
 
int main(void) {
  ios::sync_with_stdio(false);
  cin.tie(nullptr);
 
  int n; cin >> n;
  while (n--) solve();
  return 0;
}