문제
링크
풀이
#include <iostream>
#include <vector>
using namespace std;
void solve(void) {
int n, k; cin >> n >> k;
if (k > n*n-n || (n == 2 && k == 2)) {
cout << "NO";
return;
}
vector<vector<char>> ans(n, vector<char>(n, '#'));
ans[0][0] = ans[n-1][n-1] = '.';
for (int i=1; i<n-1; i++) {
ans[i][n-i-1] = '.';
}
int cur = n*n-n;
for (int i=0; i<n && cur>k; i++) for (int j=0; j<n && cur>k; j++) {
if (ans[i][j] == '.') continue;
ans[i][j] = '.';
cur--;
}
cout << "YES\n";
for (int i=0; i<n; i++) {
for (int j=0; j<n; j++) {
cout << ans[i][j];
}
cout << "\n";
}
}
int main(void) {
ios::sync_with_stdio(false);
cin.tie(nullptr);
solve();
return 0;
}