BOJ 25870 - Parity of Strings [C++]

문제

링크

풀이

#include <iostream>
#include <string>
#include <vector>
using namespace std;
 
int solve(void) {
  string s; cin >> s;
 
  vector<int> cnt(26, 0);
  for (char c : s) {
    cnt[c - 'a']++;
  }
 
  int odd = 0, even = 0;
  for (int n : cnt) {
    if (n == 0) continue;
    if (n & 1) odd++;
    else even++;
  }
 
  if (!odd && even) return 0;
  if (odd && !even) return 1;
  return 2;
}
 
int main(void) {
  ios::sync_with_stdio(false);
  cin.tie(nullptr);
  
  cout << solve();
  return 0;
}