BOJ 27468 - 2배 또는 0.5배 [C++]

문제

링크

풀이

#include <iostream>
using namespace std;
 
void solve(void){
  int n; cin >> n;
 
  cout << "YES\n";
  for (int i=1; i<=n; i++) {
    switch (i % 4) {
      case 0: cout << i; break;
      case 1: cout << i + (n % 4 == 2); break;
      case 2: cout << i + (n % 4 != 2 ? 1 : -1); break;
      case 3: cout << i - (n % 4 != 2); break;
    }
    cout << " ";
  }
}
 
int main(void) {
  ios::sync_with_stdio(false);
  cin.tie(nullptr);
 
  solve();
  return 0;
}