BOJ 33171 - いずれか片方 (Either, but Not Both) [C++]

문제

링크

풀이

#include <iostream>
using namespace std;
 
void solve(void) {
  int n; cin >> n;
  int a; cin >> a;
  int b; cin >> b;
 
  int ans = 0;
  for (int i=1; i<=n; i++) {
    if ((i % a == 0) ^ (i % b == 0)) ans++;
  }
  cout << ans;
}
 
int main(void) {
  ios::sync_with_stdio(false);
  cin.tie(nullptr);
 
  solve();
  return 0;
}