문제
풀이
#include <iostream>
using namespace std;
inline int perc(int n, int p) {
return n * p / 100;
}
void solve(void) {
int n; cin >> n;
if (n >= 1000000) cout << perc(n, 20) << " " << perc(n, 80);
else if (n >= 500000) cout << perc(n, 15) << " " << perc(n, 85);
else if (n >= 100000) cout << perc(n, 10) << " " << perc(n, 90);
else cout << perc(n, 5) << " " << perc(n, 95);
}
int main(void) {
ios::sync_with_stdio(false);
cin.tie(nullptr);
solve();
return 0;
}